Chemistry 12:  Unit 3 # 44 - 51 due Friday.  Unit 3 # 40 - 43 was due today.  Also due today was the Solubility Lab, which I did not collect.  Lab 16D will be due Monday, without a conclusion.

44.  0.20 g PbSO₄

45.  0.028 g BaCrO₄

46.  K_sp = 0.00194

47.  [Ag₂CrO₄] = 6.5 x 10^-5

48.  1.1 g/L CaSO₄

49.  2.1 x 10^-4 g/L 

50.  K_sp = 1.1 x 10^-49

51.  1.2 x 10^-10