Chemistry 12:  Unit 2 # 47-58 are due Monday.  Answers below in blue:

Chapter 2 Answers:

47.  Keq = 5.0

48.  Keq = 3.0

49. a)  Keq = 0.013

49. b)  Keq = 0.93

50.  a) Q = 0.89, so shift to Products

50.  b)  Q = 7.5  so shift to Reactants

50.  c)  Q = 4 so no shifting required

51.  a)  Q = 7.5 so shift to Products

51.  b)  Q = 1.4 x 10⁴ so shift to Reactants

51.  c)  shift to Products

52.  [SO3] = .56 M

53.  [Cl2] = .229 M

54.  Shift to products; Q = 6.954.  Shift to products; Q = 6.9

#55  [CO] = 1.17 M;   

#56  0.639 mol Tl⁺;   

#57  K_eq = .044;

58.   0.098 mol H2S  

# 59  2.5 mol of CO2 removed

#60  [HI] = .0389 M, [H₂] = [I₂] = .0055 M;  

#61  16 mol NH₃;  

#62 [N₂O₂] = .0938 M

Science 9:  Today we read section 2.3 from the old Probe 10 to learn about parasitism, commensalism, and mutualism.  Pg 32 # 1-12 are due on Monday.  Write in fine sentences, except for the Multiple Choice problems where you will report a letter only.   

# 59  2.5 mol of CO2 removed

#60  [HI] = .0389 M, [H₂] = [I₂] = .0055 M;  

#61  16 mol NH₃;  

#62 [N₂O₂] = .093Science 9: